Searched refs:newFrequentMaxJobCount (Results 1 – 1 of 1) sorted by relevance
3678 int newFrequentMaxJobCount = Math.max(MIN_BUCKET_JOB_COUNT, in processConstantLocked() local3680 if (mMaxBucketJobCounts[FREQUENT_INDEX] != newFrequentMaxJobCount) { in processConstantLocked()3681 mMaxBucketJobCounts[FREQUENT_INDEX] = newFrequentMaxJobCount; in processConstantLocked()