Searched refs:screenCenterX (Results 1 – 1 of 1) sorted by relevance
45 private var screenCenterX = 0 in <lambda>() variable57 screenCenterX = screenSizeProvider.invoke().x / 2 in <lambda>()66 onLeft = x < screenCenterX in <lambda>()136 rect.offsetTo(screenCenterX - rect.width() / 2, screenBottom - rect.height()) in <lambda>()