Searched refs:permissionUsageUseCase (Results 1 – 2 of 2) sorted by relevance
144 val permissionUsageUseCase = getPermissionGroupUsageUseCase(appOpsUsageModels) in <lambda>() constant149 permissionUsageUseCase, in <lambda>()177 val permissionUsageUseCase = getPermissionGroupUsageUseCase(appOpsUsageModels) in <lambda>() constant182 permissionUsageUseCase, in <lambda>()
186 val permissionUsageUseCase = GetPermissionGroupUsageUseCase.create(app) in create() constant187 return PermissionUsageViewModel(app, permissionRepository, permissionUsageUseCase) as T in create()